(a) Give the products of the following reactions :

(c) The reaction of `C_2 H_5 OH` with `NaBr` in the presence of `H_2 S O_4` is slow, but when trimethy1 sily1 chloride `(Me_3 SiC1)` is added to it, reaction proceeds very fast. Why ?

Explanation

(a) When (A) undergoes `SN^1` reaction, both cis and trans products are formed because the nucleophile can approach the intermediate carbocation from either side.

When (A) undergoes `SN^2` reaction, only the trans product is obtained because the nucleophile approaches the back-side of `C-bond` to the leaving group.


`Me_3 SiCI` attaches itself with the `O` atom of `(OH)` group. thus making it a better leaving group resulting in faster `SN^2` reactions.