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In SN^2, solvolysis RX in which the solv...

In `SN^2`, solvolysis `RX` in which the solvent is a nucleophile, what is the order and molecularity of the reaction ?

A

First order , unimolecular

B

First order , bimolecular

C

Second order , bimolecular

D

Pseudo first-order , bimolecular

Text Solution

Verified by Experts

The correct Answer is:
D
`SN^2` solvolysis reaction in bimolecular and the rate law is :
Rate `= K[RX] ["Solvent"]`
Since the concentration of the solvent is very large and exceeds the amount of `RX`, therefore, its concentration is constant. Hence the reaction will follow pseudo first-order rate law.
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