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underset((A))(PhCOOH)underset(underset((...

`underset((A))(PhCOOH)underset(underset((ii)Ag_(2)O //Pt//MeOH)((ii)CH_(2)N_(2)))overset((i)SOCI_(2))rarr (B)`
Product `(B)` is :

A

`PhCONH_2`

B

`PhCH_2 COOH`

C

`PhCH_2 COOMe`

D

`PhCONHMe`

Text Solution

Verified by Experts

The correct Answer is:
C
Arndt-Eistert reaction . The product `PhCH=C=O` (ketone) reacts with `MeOH` to give ester `(PhCH_2 COOMe)` (step up by one `C` atom).
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