An enantiomerically pure is treated with racemic mixture of an alcohol having one chiral carbon. The ester formed will be :

Options

A. Optically active mixture
B. Pure enantiomer
C. Mesi-compound
D. Racemic mixture

Answer

A

Explanation

`(d) or (+) RCOOH + (dl) or (+-) R' OH rarr (dd) or (+)(+) RCOOR' (I) and (dl) or (+) (-) RCOOR's (II)`
Which optically active acid reacts with racemic mixture of alcohol, it forms two types `(I and II)` of isomeric esters. In each, the configuration of chiral centre of acid would remain the same. So the mixture would be optically active.