The difference between angular speed fo ...

The difference between angular speed fo minute hand and second hand of a clock is

`(59pi)/(900) rad/s`

`(59pi)/(1800) rad/s`

`(59pi)/(2400) rad/s`

`(59pi)/(3600) rad/s`

Text Solution

Verified by Experts

The correct Answer is:

Angular speed of minute hand
`omega_(m)=360^(@)` per hour
`=(360x(pi)/(180))` per hour =`(2pi)/(3600)` rad/s
angular speed of second hand
`omega_(s)=360^(@)` per minute =`(2pi)/(60)` rad / s
`therefore` differnce between angular speeds of minute hand and second hand of a clock
`=omega_(m)-omega_(s)=(2pi)/(3600)-(2pi)/(60)=-(59pi)/(1800`
so difference between `omega_(m)` and `omega_(s)` is `(59pi)/(1800)` rad/s

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The difference between angular speed of minute hand and second hand of a clock is

`(59pi)/900rad//s`

`(59pi)/1800rad//s`

`(59pi)/2400rad//s`

`(59pi)/3600rad//s`

The relative angular speed of the minute hand and second hand of a clock is

`(29pi)/(1800) rad//s`

`(39pi)/(1800) rad //s`

`(49 pi)/(1800 ) rad //s`

`(59 pi )/(1800) rad//s`

The ratio of angular speeds of minutes hand and seconds hand in a watch is

`60:1`

`30:1`

`1:30`

`1:60`