The difference between angular speed fo minute hand and second hand of a clock is
A
`(59pi)/(900) rad/s`
B
`(59pi)/(1800) rad/s`
C
`(59pi)/(2400) rad/s`
D
`(59pi)/(3600) rad/s`
Text Solution
Verified by Experts
The correct Answer is:
b
Angular speed of minute hand `omega_(m)=360^(@)` per hour `=(360x(pi)/(180))` per hour =`(2pi)/(3600)` rad/s angular speed of second hand `omega_(s)=360^(@)` per minute =`(2pi)/(60)` rad / s `therefore` differnce between angular speeds of minute hand and second hand of a clock `=omega_(m)-omega_(s)=(2pi)/(3600)-(2pi)/(60)=-(59pi)/(1800` so difference between `omega_(m)` and `omega_(s)` is `(59pi)/(1800)` rad/s
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