A satellite of mass m s revolving in circlular orbit of radius r aroiund the earth its angular momentum w.r.t the centre of its orbit is (M=mass of earth G= universal gravitational constant )
A
`(GMmr)^(1//2)`
B
`(GM^(2)mr)^(1//2)`
C
`(GMm^(2)r^(2))^(1//2)`
D
`(GM^(2)m^(2)r)^(1//2)`
Text Solution
Verified by Experts
The correct Answer is:
b
Orbital speed of the satelite `V= sqrt(GM)/(r )` angular momentum of the satellite `L=mvr=mrxxsqrt(GM)/(r )=(GM^(2)r)^(1//2)`
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