Let `g_(h)` and `g_(d)` be the acceleartion due to gravity at height h above the earth s surface and at depth d below the earth 's surface respectively if `g_(h)=g_(d)` then the relation between h and d is
A
d=h
B
`d=(h)/(2)`
C
`d=(h)/(4)`
D
d=2h
Text Solution
Verified by Experts
The correct Answer is:
a
Acceleration due to gravity at a height h above the earth 's surface `g_(h)-(1-2h)/(R )` Acceration due to gravity at a depth d below the earth surface `g_(d)=(1-(d))/(R )` `therefore (1-(2h))/(R )=(1-(d))/(R )` or `(1-(2h))/(r )=(1-(d))/(R )-(d)/(R ) rarr (2h)/(R )=(d)/(R)` `rarr d=2h`
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