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Two coils have a mutual inductance of 0.01 H. The current in the first coil changes according to equation, I = 5 sin 200`pi`t. The maximum value of emf induced in the second coil is

A

`10piV`

B

`0.1piV`

C

`piV`

D

`0.01piV`

Text Solution

Verified by Experts

The correct Answer is:
A

Given, mutual inductance in the coil, M = 0.01 H
and current in coil , I = 5sin200 `pi`t. Emf induced in secondary coil is given,
`e=M(dl)/(dt)`
putting the value in above relation
`e=0.01xxd/(dt)(5sin200pit)`
`=0.01xx5xx200picos200pit=10picos200pit`
Compairing the above equation with the general equation of induced emf, which is represented as,
`e=e_(0)cosomegat`
where, `e_(0)` is the maximum value of the emf.
`therefore` In the question, the maximum value of emf induced in the coil is, `e_(0)=10piV`
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