In a series circuit `R=300Omega, L=0.9H, C=2.0 muF` and `omega=1000rad//sec` . The impedence of the circuit is

Options

A. `500Omega`
B. `1300Omega`
C. `400Omega`
D. `900Omega`

Answer

A

Explanation

Substituting the given values in the above equation, we get
`rArrZ=sqrt(300^(2)+(1000xx0.9-1/(1000xx2xx10^(-6)))^(2))`
`rArrZ=sqrt(90000+(900-500)^(2))`
`rArrZ=sqrt(250000)=500Omega`
Hence, the impedance of LCRcircuit is 500 `Omega`.