Resolving power of a telescope will be more, fi the diameter (a) of the objective is

Options

A. independent of the diameter of the objective
B. low
C. zero
D. high

Answer

D

Explanation

Resolving power of a telescope is given,
`x=a/(1.22lamda)!xpropa`
where, a = diameter/aperture of objective a telescope and `lamda`= wavelength of light.
when the aperture (diameter) of objective is large, then its resolving power is high.