The dimensions of torque are same as that of

Options

A. moment of force
B. pressure.
C. acceleration
D. impulse

Answer

A

Explanation

Torque is expressed as,
`tau`=force ( F) `xx` perpendicular distance (r )
So, `[tau]=[F]xx[r]=[MLT^(-2)][L]`
`=[ML^(2)T^(-2)]`
Now, the dimension of moment of force = force `xx` distance = `[MLT^(-2)]xx[L^(1)] =[ML^(2)T^(-2)]`
(b) Dimension of pressure=Force`xx["Area"}^(-2)`
(c) Dimension of acceleration = `[M^(0)L^(1)T^(-2)]`
(d) Dimension of impulse= [Force] `xx` [time]
`=[MLT^(-2)][T^(1)]=MLT^(-1)`
As, the torque has dimension `[ML^(2)T^(-2)]` which is correctly matched by the dimensions of moment of force. So, option (a) is correct.