When photons of energy hv fall on a metal plate of work function '`W_(0)`' , photoelectrons of maximum kinetic energy 'K' are ejected. If the frequency of the radiation is doubted, the maximum kinetic energy of the ejected photoelectrons will be

Options

A. `K+W_(0)`
B. K+hv
C. K
D. 2K

Answer

B

Explanation

Given, energy of photon == hv, work function = `W_(0)` and maximum kinetic energy = K
So, from the Einstein's photoelectric equation
`E = K + W_(0) ⇒ h v = K + W_(0)`
`!K=hv-W_(0)`
If frequency of the radiation is doubled, then Einstein's photoelectric equation changed as
`K'=h(2v)-W_(0)`
By substracting the Eq. (i) from (ii), we get
`K'-K=h(2v)-hv-W_(0)+W_(0)`
`!K'=K+hv`
So. option (b) is correct.