The ratio of the dimensions of Planck's constant and that of moment of inertia has the dimensions of

Options

A. angular momentum
B. velocity
C. frequency
D. time

Answer

C

Explanation

The dimensions of Planck's constant
` [h]=([E])/( [V] )= ( [ML^(2) T^(-2) ])/([ M^(0) L^(0) T^(-1)]) `
and that moment of inertia
` [1] =[M][R] ^(2) =[M ][L] ^(2) =[ML^(2) T^(0) ]`
` therefore " " ([h])/( [I]) =( [ML^(2) T^(-1) ]) /( [ML^(2) T^(0) ]) =[T^(-1) ] =[v]`
Thus the ratio of diminations of Plancks constant to that at moment of inertia is the dimensions of frequency.