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Statement I: Glucose gives a reddish-bro...

Statement I: Glucose gives a reddish-brown precipitate with fehling's solution.
Statement I: Reaction of glucose with fehling's solution gives `CuO` and gluconic acid.

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The correct Answer is:
C
Statement `I` is true but statement `II` is false because `Cu^(2+)` of Fehling's solution, `[Cu (NH_(3))_(4)]^(2+)(OH)_(2)`, is reduced to `Cu^(+)` to give a red precpitate of `Cu_(2)O`.
`OCH(CHOH)_(4)CH_(2)OH+Cu^(2+)+overset(Θ)OH rarr .^(Θ)OOC-(CHOH)_(4)CH_(2)OH" gluconic acid" +Cu_(2)O+H_(2)O`
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Statement I : Glucose gives a reddish-brown precipitate with Fehling's solution
Statement II : Reaction of glucose with Fehling's solution gives `CuO` and gluconic acid

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Assertion : Glucose gives a reddish brown precipitate with Fehiling's solution.
Reason : Reaction of glucose with Fehiling's solution gives CuO and gluconic acid.

Statement-I: Glucose gives a reddish-brown precipitate with Fehiling's solution
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Statement-2: Reaction of glucose with Fehling's solution gives CuO and gluconic acid

Statement -1 Glucose gives a reddish brown precipitate with Fehling's solution. Statement -2 : Reaction of glucose with Fehling's solution gives CuO and gluconic acid.

वक्तव्य I ग्लूकोस, फेहलिंग विलयन के साथ लाल - भूरा अवक्षेप देता है |
वक्तव्य II ग्लूकोस की फेहलिंग विलयन से अभिक्रिया के फलस्वरूप CuO तथा ग्लूकोनिक अम्ल बनते हैं|

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