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If u1 and u2 are the units selected in t...

If `u_1` and `u_2` are the units selected in two systems of measurement and `n_1` and `n_2` their numerical values, then

A

`n_1u_1=n_2u_2`

B

`n_1u_1+n_2u_2=0`

C

`n_1n_2=u_1u_2`

D

`(n_1+u_1)l=(n_2+u_2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Pysical quantity `(p)=` numerical value `(n)xxunit(u)` If pysical quantity remains constant then `nprop(1)/(u)` `because` `n_1u_1=n_2u_2`.
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Knowledge Check

  • If u_(1) and u_(2) are the selected in two system of measurement and n_(1) and n_(2) their nomerical values, then

    A
    `n_(1)u_(1)=n_(2)u_(2)`
    B
    `n_(1)u_(1)+n_(2)u_(2) = 0`
    C
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    D
    `(n_(1) + u_(1)) =(n_(2) + u_(2))`

  • STATEMENT 1 When the unit for measurement of a quantity is changed, its numerical value changes STATEMENT 2 Smaller the unit of measurement matter is its numerical value

    A
    Statement-1 is True , Statement-2 is True ,Statement-2 is a correct explanation for Statement-1
    B
    Statement-1 is True , Statement-2 is True ,Statement-2 is NOT a correct explanation for Statement-1
    C
    Statement-1 is True , Statement-2 is False
    D
    Statement-1 is False, Statement-2 is True

  • The numerical values and units of a physical quantity in two different system of units are n_(1), n_(2) and u_(1), u_(2) respectively. Then

    A
    `n_(1)u_(2)=n_(2)u_(1)`
    B
    `n_(1)u_(1)^(2)=n_(2)u_(2)^(2)`
    C
    `n_(1)=n_(2) & u_(1)=u_(2)`
    D
    `n_(1)u_(1)=n_(2)u_(2)`

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