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The velocity of a freely falling body ch...

The velocity of a freely falling body changes as `g^ph^q`where g is acceleration due to gravity and h is the height. The values of p and q are

A

`1`,`(1)/(2)`

B

`(1)/(2)`,`(1)/(2)`

C

`(1)/(2)`,`1`

D

1,1

Text Solution

Verified by Experts

The correct Answer is:
B

`upsilonpropg^ph^q`(given)
By substituting the dimension of each quantity and comparing the powers in both sides we get `[LT^-1]=[LT^-2]^p[L]^q`
`implies=p+q=1`,`-2p=-1`,because `p=(1)/(2)`,`q=(1)/(2)`
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