A force `F` is given by `F = at + bt^(2)` , where `t` is time . What are the dimensions of `a and b`?

Options

A. `MLT^(-3)` and `ML^(2)T^(-4)`
B. `MLT^(-3)` and `MLT^(-4)`
C. `MLT^(-1)` and `MLT^(0)`
D. `MLT^(-4)` and `MLT^(1)`

Answer

B

Explanation

From the principle of dimensional homogeneity`[a]=[(F)/(t)]=[MLT^-3]` and `[b]=[(F)/(t^2)]=[MLT^-4]`