The relative density of material of a body is found by weighting it first in air and then in water . If the weight in air is `( 5.00 +- 0.05) N` and the weight in water is `(4.00 +- 0.05) N`. Find the relative density along with the maximum permissible percentage error.

Options

A. `5.0+-11%`
B. `50+-1%`
C. `5.0+-6%`
D. `1.25+-5%`

Answer

A

Explanation

Weight in air `(5.00+0.05)N`
Weight in water`=(4.00+-0.05)N`
Loss of weight in water `=(1.00+-0.1)N`
`now relative density`=(weight i n air)/(weight loss i n water)`
i.e. `R.D=(5.00+-0.05)/(1.00+-0.1)`
Now relative density with max permissible error
`=(5.00)/(1.00)+-((0.5)/(5.00)+(0.1)/(1.00))xx100=5.0+-(1+10)%`
`=5.0+-11%`