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The period of oscillation of a simple pe...

The period of oscillation of a simple pendulum in the experiment is recorded as `2.63 s , 2.56 s , 2.42 s , 2.71 s , and 2.80 s`. Find the average absolute error.

A

0.1s

B

0.11s

C

0.01s

D

1.0s

Text Solution

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The correct Answer is:
B
Average value`=(2.63+2.56+2.42+2.71+2.80)/(5)`
`=2.62`sec
Now, `|triangleT_1|=2.63-2.62=0.01`
`|triangleT_2|=2.62-2.56=0.06`
`|triangleT_3|=2.62-2.42=0.20`
`|triangleT_4|=2.71-2.62=0.09`
`|triangleT_5|=2.80-2.62=0.18`
mean absolute error
`triangleT=(|triangle_1|+|triangleT_2|+|triangleT_3|+|triangleT_4|+|triangleT_5|)/(5)`
`=(0.54)/(5)=0.108=0.11` sec
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