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If y=cos(sinx^2),then at x=sqrt((pi)/(2)...

If `y=cos(sinx^2)`,then at `x=sqrt((pi)/(2))`,`(dy)/(dx)=`

A

-2

B

2

C

`-2sqrt((pi)/(2))`

D

0

Text Solution

Verified by Experts

The correct Answer is:
D
Since `(dy)/(dx)=-sin(sinx^(2)).cosx^(2).2x`
Therefore at `x=sqrt((pi)/(2)),cosx^(2)=cos(pi)/(2)=0implies(dy)/(dx)=0`
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