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The magnitudes of vectors vecA,vecB and ...

The magnitudes of vectors `vecA,vecB and vecC` are 3,4 and 5 units respectively. If `vecA+vecB= vecC`, the angle between `vecA` and vecB` is

A

`(pi)/(2)`

B

`cos^(-1)(0.6)`

C

`tan^(-1)((7)/(5))`

D

`(pi)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
A


`C=sqrt(A^(2)+B^(2))`
`=sqrt(3^(2)+4^(2))=5`
Angle between `vec(A)` and `vec(B)` is `(pi)/(2)`
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