A scooter going due east at `10 ms^(-1)` turns right through an angle of `90^(@)`. If the speed of the scooter remain unchanged in taking turn, the change is the velocity the scooter is

Options

A. `20.0ms^(-1)` south eastern direction
B. zero
C. `10.0ms^(-1)` in southern direction
D. `14.14ms^(-1)` in south-west direction

Answer

D

Explanation

If the magnitude of vector remains same, only directions change by `theta` then
`vec(trianglev)=vec(v_2)-vec(v_1),vec(trianglev)=vec(v_2)+(-vec(v_1))`
Magnitude of change in vertor `|vectrianglev|=2xsin((triangle)/(2))`
`|vec(trianglev)|=2xx10xxsin((90^@)/(2))=10sqrt(2)=14.14(m)/(s)`
Direction is south-west as shown in figure.