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The relation between time t and displace...

The relation between time t and displacement x is `t = alpha x^2 + beta x,` where `alpha and beta` are constants. The retardation is

A

`2alphav^3`

B

`2betav^3`

C

`2alphabetav^3`

D

`2beta^2v^3`

Text Solution

Verified by Experts

The correct Answer is:
A
`(dt)/(dx)=2alphax+betaimpliesv=(1)/(2alpha+beta)` `because` `a=(dv)/(dt)=(dv)/(dx)(dx)/(dt)`
`a=v(dv)/(dx)=(-v2alpha)/((2alphax+beta)^2)=-2alphav.v^2=-2alphav^3`
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