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The relation 3t=sqrt(3x)+6 describe the ...

The relation `3t=sqrt(3x)+6` describe the displacement of a particle in one direction where x is in metres and t in sec.
The displacement, when velocity is zero is

A

24 metres

B

12 metres

C

5 metres

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D
`3t=sqrt(3x)+6implies3x=(3t-6)^2`
`impliesx=3t^2-12t+12`
`v=(dx)/(dt)=6t-12`, for `v=0`,`t=2` sec
`x=3(2)^2-12xx2+12=0`
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