The velocity of a particle moving in the positive direction of x-axis veries as `v=10sqrtx`. Assuming that at `t=0`, particle was at `x=0`

Options

A. The initial velocity of the particle is zero
B. the initial velocity of the particle is `2.5(m)/(s)`.
C. The accelration of the particle is `2.5(m)/(s^2)`.
D. The acceleration of the particle is `50(m)/(s^2)`.

Answer

A, D

Explanation

Given `v=10sqrtx`
Putting `x=0` gives `v=0`, so initial velocity of the particle is zero.
`a=(dv)/(dt)=(10)/(2sqrtx)(dx)/(dt)`
`impliesa=(5)/(sqrtx)v=(5)/(sqrtx)10sqrtx=50(m)/(s^2)`