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A particle is projected from a point (0,1) of Y-axis (assume + Y direction vertically upwards) aiming towards a point (4,9). It fell on ground along x axis in 1 sec. Taking `g=10(m)/(s^2)` and all coordinate in metres. Find the X-coordinate where it fell.

A

(3,0)

B

(4,0)

C

(2,0)

D

(2`sqrt5`,0)

Text Solution

Verified by Experts

The correct Answer is:
C

`tantheta=(9-1)/(4-0)=2`
Now, `-1=usintheta(1)-(1)/(2)g(1)^2`
`usintheta=4` and `theta=(2)/(sqrt5)impliesu=2sqrt5`
`now, `x=ucostheta(1)=(2sqrt5)xx(1)/(sqrt5)=2`m
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