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Two particles are projected from the sam...

Two particles are projected from the same point with the same speed at different angles `theta_1` & `theta_2` to the horizontal. They have the same range. Their times of flight are `t_1` & `t_2` respectily

A

`(t_1)/(t_2)=tan^2theta_1`

B

`(t_1)/(sintheta_1)=(t_2)/(costheta_2)`

C

`(t_1)/(t_2)=tantheta_1`

D

`(t_1)/(t_2)=tan^2theta_2`

Text Solution

Verified by Experts

The correct Answer is:
C
`R=(u^2sin2theta)/(g)` is same for angles `theta`&`90^@-theta`.
`t_1=(2usintheta_1)/(g)=(2usin(90^@-theta_2))/(g)`
`t_2=(2usintheta_2)/(g)=2usin((90^@-theta_1))/(g)`
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