In the climax of a movie, the hero jumps from a helicopter and the villain chasing the hero also jumps from the same level . After sometime when they come at same horizontal level, the villain fires bullet horizontally towards the hero, Both were falling with constant acceleration `2(m)/(s^2), because of parachute, Assuming the hero to be within the range of bullet, which of the following is correct.

Options

A. bullet will hit the hero
B. bullet will pass above the hero
C. bullet will pass below the hero
D. bullet will definitely hit the hero, if both were falling with constant acceleration `g` instead of `2(m)/(s^2)`

Explanation

To solve the problem, we need to analyze the motion of both the hero and the villain, as well as the bullet fired by the villain.

### Step-by-Step Solution:

1. **Understanding the Scenario**:
- Both the hero and the villain jump from the same height and fall under the influence of gravity with a downward acceleration of \(2 \, \text{m/s}^2\) due to their parachutes.
- The villain fires a bullet horizontally when he reaches the same horizontal level as the hero.

2. **Vertical Motion of the Hero and Villain**:
- The vertical motion of both the hero and the villain can be described by the equation of motion:
\[ h = \frac{1}{2} a t^2 \]
where \(h\) is the distance fallen, \(a = 2 \, \text{m/s}^2\), and \(t\) is the time of fall.

3. **Vertical Motion of the Bullet**:
- The bullet, once fired, will also experience a downward acceleration due to gravity, which is approximately \(9.8 \, \text{m/s}^2\).
- The vertical motion of the bullet can also be described by the same equation of motion:
\[ h_b = \frac{1}{2} g t_b^2 \]
where \(g \approx 9.8 \, \text{m/s}^2\) and \(t_b\) is the time taken for the bullet to fall.

4. **Comparing the Vertical Distances**:
- At the moment the villain fires the bullet, both the hero and the villain have fallen the same vertical distance \(h\) after time \(t\).
- The bullet will start falling from the same height as the hero but will accelerate downwards faster due to the greater gravitational acceleration.

5. **Conclusion**:
- Since the bullet falls faster than the hero (because \(9.8 \, \text{m/s}^2 > 2 \, \text{m/s}^2\)), it will pass below the hero as both continue to fall.
- Therefore, the correct answer is that the bullet will pass below the hero.

### Final Answer:
The bullet will pass below the hero.