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A paarticle moves in the xy-plane under ...

A paarticle moves in the xy-plane under the action of a force F such that the componentes of its linear momentum p at any time t and `p_(x)=2cos` t, `p_(y)=2sin` t. the eangle between F and p at time l is

A

`90^@`

B

`0^@`

C

`180^@`

D

`30^@`

Text Solution

Verified by Experts

The correct Answer is:
A
Given that `vecp=p_xhati+p_yhatj=2costhati+2sinthatj`
`vecF=(vec(dp))/(dt)=-2sinthati+2costhatj`
Now, `vecF.vecp=0` i.e. angle between `vecF` and `vecp` is `90^@`
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