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In the shown mass pulley system, pulleys...


In the shown mass pulley system, pulleys and string are massless. The one end of the string is pulleed by the force `F=2mg`. The acceleration of the block will be

A

`(g)/(2)`

B

0

C

Greater than `vecv`

D

3g

Text Solution

Verified by Experts

The correct Answer is:
D

F.B.D. of block
`implies2T-mg=ma`
`a=3g`
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Knowledge Check

  • In the shown mass pulley system, pulleys and string are massless. The one end of the string is pulled by the force F = mg. The acceleration of the block will be :

    A
    `g//2`
    B
    0
    C
    g
    D
    3g

  • In the arrangement shown, the pulleys and strings are massless. The acceleration of block B is :

    A
    g/2
    B
    5g/3
    C
    2g/3
    D
    2g/5

  • In the diagram shown in figure, both pulleys and strings are massless. The acceleration of 2 kg block is

    A
    `2.5 m//s^(2) (uarr)`
    B
    `5 m//s^(2) (uarr)`
    C
    `7.5 m//s^(2) (darr)`
    D
    `10 m//s^(2) (uarr)`

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