In the figure shown , A and B are free of to move. All the surfaces are smooth. `(0 lt theta lt 90^(@))`

Options

A. the accelration of A will be more than `gsintheta`
B. the acceleration of A will beless than `gsintheta`
C. normal force on A due to B will be more than `mgcostheta`
D. normal force on A due to B will be less than `mgcostheta`

Answer

A, D

Explanation

`ma_0sintheta+N=mgcostheta`
`impliesmgcostheta`
`impliesN=mgcostheta-ma_0sintheta`
`impliesNltmgcostheta`
Hence, (D) is true.
`ma_0costheta+mgsintheta=ma`
`impliesa=gsintheta+a_0costheta`
Hence, acceleration of A
`=sqrt((a-a_0costheta)^2+(a_0sintheta)^2)gtgsintheta`