A smooth wedge of mass M is pushed with an acceleration `a=gtantheta` and a block of mass m is projected down the slant with a velocity v relative to the wedge.
`The horizontal force applied on the wedge is:

Options

A. `(M+m)gsintheta`
B. `(M+m)gcostheta`
C. `Mgsin^2theta+Mg`
D. `(M+m)g+mgcos^2theta`

Answer

D

Explanation

`a=gtantheta`
`(F)/((m+M))=gtantheta`
`F=(m+M)gtantheta`