A fireman of mass 60 kg slides down a pole. He is pressing the pole with a force of 600N. The coefficient of friction between the hands and the pole is 0.5, with what acceleration will the fireman slide down `(g=10(m)/(s^2)`)

Options

A. `1(m)/(s^2)`
B. `2.5(m)/(s^2)`
C. `10(m)/(s^2)`
D. `5(m)/(s^2)`

Answer

D

Explanation

Net downward accelration `=(weight-f riction fo rce)/(Mass)`
`=((mg-muR))/(m)=(60xx10-0.5xx600)/(60)`
`=(300)/(60)=5(m)/(s^2)`