Let the line `(x-2)/3=(y-1)/(-5)=(z+2)/2` lie in the plane `x""+""3y""alphaz""+beta=""0` . Then `(alpha,beta)` equals (1) `(6,""""-17)` (2) `(-6,""7)` (3) `(5,"" -15)` (4) `(-5,""5)`

Explanation

`Dr's` of line = (3,-5,2)

`Dr's` of line `_|_` to plane = (1,3,-2)

two lines are `_|_` , if `a_1a_2 + b_1b_2 + c_1c_2 = 0`

`3 xx1 -5xx3 + 2 xx (- alpha) = 0`

`-12 = 2 alpha`

`alpha = -6`

plane passing from point (2,1,-2)

`2+3+6(-2) + beta = 0`

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