ABCD is a rectangle (Fig. 11.31) in which DP and BQ are perpendiculars from D and B respectively on diagonal AC. Show that(1) `Delta ADP = Delta ACBQ` (ii) `/_ADP = /_CBQ`(iii) DP = BQ

ABCD is a parallelogram and AP and CQ are the perpendiculars from vertices A and C on its diagonal BD (See fig.) Show that Delta APB ~= Delta CQD .

In Figure,ABCD is a rectangle.BM and DN are perpendicular from B and D respectively on AC. Prove that MBC~=DNA( ii) BM=DN

line l is the bisector of an angle /_A\ a n d/_B is any point on l. BP and BQ are perpendiculars from B to the arms of /_A . Show that: (i) DeltaA P B~=DeltaA Q B (ii) BP = BQ or B is equidistant from the arms of /_A

ABC is a triangle in which AB=AC.D and E are points on the sides AB and AC respectively,such that AD=AE .Show that the points ' B

Line l is the bisector of an angle angle A and B is any point on l. BP and BQ are perpendiculars from B to the arms of angle A (see Fig. 7.20). Show that: (i) triangle APB cong triangle AQB (ii) BP = BQ or B is equidistant from the arms of angle A .

In an adjoining figure,ABCD is a rectangle, BM and DN are perpendicular from B and D on AC( i) Is Delta BMC=Delta DNA

ABCD is a quadrilateral in which P, Q, R and S are the mid-points of sides AB, BC, CD and DA respectively (See Fig. AC is a diagonal Show that SR II AC and SR = 1/2 AC .

ABCD is a quadrilateral in which P, Q, R and S are the mid-points of sides AB, BC, CD and DA respectively (See Fig. AC is a diagonal Show that SR II AC and SR = 1/2 AC .

Ray 1 is the bisector of an angle angle A and B is any point on I. BP and BQ are perpendiculars from B to the arms of angle A (see the given figure). Show that: (i) triangleAPB=triangleAQB (ii) BP = BQ or B is equidistant from the arms of angleA

In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ (see Fig. ) Show that Delta APD ~= Delta CQB .