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Distance between two parallel planes `2x""+""y""+""2z""=""8` and `4x""+""2y""+""4z""+""5""=""0` is (1) `5/2` (2) `7/2` (3) `9/2` (4) `3/2`

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given planes are : `(2x+y+2z=8)xx 2 = 4x + 2y + 4z = 16`
`4x+2y + 4z = -5`
distance`= (|16 - (-5)|)/sqrt((4)^2 + (2)^2 + (4)^2)`
`= 21/sqrt36 = 21/6 = 7/2`
Answer
option 2 is correct
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