Home
Class 12
MATHS
Prove that the normal chord at the point...

Prove that the normal chord at the point other than origin whose ordinate is equal to its abscissa subtends a right angle at the focus.

Text Solution

Verified by Experts

The correct Answer is:
cearly `m_(1)m_(2)=-1, "so that" SP bot SQ`
Promotional Banner

Topper's Solved these Questions

  • PARABOLA

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise EXERCISE-3 (a) i.|1 Videos
  • PARABOLA

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise EXERCISE-3 (a)|10 Videos
  • MEASURES OF DISPERSION

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise EXERCISE|9 Videos
  • PARTIAL FRACTIONS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise EXERCISE- 7|32 Videos

Similar Questions

Explore conceptually related problems

Prove that the normal chord at the point on y^(2) = 4ax , other than origin whose ordinate is equal to its abscissa subtends a right angle at the focus.

The point on the parabola y^(2)=36x whose ordinate is three times its abscissa is

If the normal chord drawn at the point P(t) to the parabola y^(2) = 4ax subtends a right angle at the focus, then show that , = pm2

Equation of normal to y^(2) = 4x at the point whose ordinate is 4 is

Find the locus of a point P If the join of the points (2,3) and (-1,5) subtends a right angle at P.

Find the locus of a point P if the join of the points (2,3) and (-1,5) subtends a right angle at P.

If a normal chord at a poit t( ne 0) on the parabola y^(2) = 9x subtends a right angle at its vertex, then t =

Prove that the portion or the tangent intercepted,between the point of contact and the directrix of the parabola y^(2)= 4ax subtends a right angle at its focuc.