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A regular hexagon of side 10 cm has a ch...

A regular hexagon of side 10 cm has a charge `5muC` each of its vertices, Calaculate the potential at the centre of the hexagon.

Text Solution

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O is centre of hexagon. ABCDEFA of each side 10cm. As its clear from the figure, OAB,OBC etc. are equilateral triangles.
Therefore
`OA=OB-OC-OD=OE=OF`
`=r=10cm=10^(-1)m`
As potential is scalar, there for C potential at O is

`V=6xx(q)/(4piepsi_0r)=(9xx10^9xx6xx5xx10^-6)/(10^-1)`
`=2.7xx10^(6)V`.
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