`int (x^(2))/(1-x^(6))dx` का मान है

Explanation

`I= int (x^(2))/(1-x^(-6))dx` माना `x^(3)=trArr 3x^(2)dx=dt`
`:. I =(1)/(3)int (dt)/(1-t^(2))=(1)/(3)xx(1)/(2)"log"[(1+t)/(1-t)]+C`
`=(1)/(6)"log" [(1-t)/(1-t)]+C`
`=(1)/(6)"log"[(1+x^(3))/(1-x^(3))]+C`