The velocity-time graph of a linear motion os shown figure. The distance from the starting point after `8 sec` is.

Options

A. 5 m
B. 16 m
C. 8 m
D. 19 m

Answer

A

Explanation

Distance from the starting point is equal to displacement.
Displacement = area of `v-t` graph
=`(1)/(2)[4 + 2]4 - (1)/(2)[4 + 3] xx 2 = 5 m`
Here distance travelled is not asked, but the distance from the the starting point.