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The velocity-time graph of a linear moti...

The velocity-time graph of a linear motion os shown figure. The distance from the starting point after `8 sec` is.

A

5 m

B

16 m

C

8 m

D

19 m

Text Solution

Verified by Experts

The correct Answer is:
A

Distance from the starting point is equal to displacement.
Displacement = area of `v-t` graph
=`(1)/(2)[4 + 2]4 - (1)/(2)[4 + 3] xx 2 = 5 m`
Here distance travelled is not asked, but the distance from the the starting point.
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Knowledge Check

  • The velocity time graph of a linear motion is shown in the figure. The distance from the starting point after 8 seconds will be .

    A
    18 m
    B
    6 m
    C
    8 m
    D
    none of these
  • The velocity-time graph of a linear motion is shown below. The distance from the origin after 8 seconds is :

    A
    18 m
    B
    16 m
    C
    8 m
    D
    6 m
  • The velocity-time graph of a linear motion is shown in figure. The displacement & distance from the origin after 8 sec is :-

    A
    `5m, 19m`
    B
    `16 m, 22m`
    C
    `8 m, 19 m`
    D
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