Velocity `v` of a particle moving along x axis as a function of time is given by `v = 2t m//s`. Initially the particle is to the right of the origin and `2 m` away from it. Find the position (distance from origin) of the particle after first `3 s`.

Options

A. 5 m
B. 7 m
C. 11 m
D. 9 m

Answer

C

Explanation

`v = 2t`
`underset(z)overset(x)(int) dx = underset(0)overset(3)(int) v dt rArr x - 2 = underset(0)overset(3)(int) 2t dt`
`rArr x-2 = [(2 t^2)/(2)]_0^3 rArr x = 11 m`.