A particle projected with velocity u at ...

A particle projected with velocity u at angle `theta` with horizontal at t=0. What is the magnitude of change in the velocity of the particle when it is at maximum height?

`(u cos theta)/2`

`u cos theta`

`u sin theta`

none of these

Text Solution

Verified by Experts

The correct Answer is:

`vecu_(i)=u cos theta hati+u sin theta hatj`
`vecu_(f)=u cos theta hati`
`Deltavecu=vecu_(f)-vecu_(i)=-u sin thetahatj`
`|Deltavecu|=u sin theta`

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