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For angles of projection of a projectile...

For angles of projection of a projectile at angle `(45^(@) - theta) and (45^(@)+ theta)`, the horizontal ranges described by the projectile are in the ratio of :

A

`2:1`

B

`1:2`

C

`1:1`

D

`2:3`

Text Solution

Verified by Experts

The correct Answer is:
C

For a projectile launched with velocity u at an angle `theta`, the horizontal range is given by
`R=(u^(2)sin 2 theta)/g`
(i) for `theta_(1)=45^(@)- theta`
`R_(1)=(u^(2)sin (90^(@)-2 theta))/g=(u^(2)cos 2 theta)/g`
(ii) For `theta_(2)=45^(@)+ theta`
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