The range of a projectile launched at an angle of `15^(@)` with horizontal is `1.5km`. The range of projectile when launched at an angle of `45^(@)` to the horizontal is

Options

A. `1.5km`
B. `3km`
C. `6km`
D. `0.75km`

Answer

B

Explanation

`R_(15^(@))=(u^(2))/g sin2xx15^(@)`
`implies 1.5=(u^(2))/g sin30^(@)`
`implies (u^(2))/g=1.5/(sin 30^(@))=1.5xx2=3 km`.
and `R_(45^(@))=(u^(2))/g sin2xx45^(@)=(u^(2))/g=3km`