During a projectile motion if the maximum height equal the horizontal range, then the angle of projection with the horizontal is :

Options

A. `tan^(-1)(1)`
B. `tan^(-1)(2)`
C. `tan^(-1)(3)`
D. `tan^(-1)(4)`

Answer

D

Explanation

`H=(u^(2) sin^(2) theta)/(2g) and R=(u^(2) sin 2 theta)/g`
Since `H=R(u^(2) sin^(2) theta)/(2g) =(u^(2)xx2sin theta cos theta)/g`
or `tan theta=4 or theta=tan^(-1)(4)`