A particle is projected form a trolley car with a velocity `vecv`. If the trolley can moves with an acceleration `veca` towards right, which of the following remain unchanged relative to both ground and trolley car?

Options

A. Range
B. Maximum range
C. Time of flight
D. horizontal velocity

Answer

c

Explanation

Vertical component of projectile relative to trolley,
`v_(yT)=v sin theta`
And vertical component of projectile relative to ground
`v_(yG)= v sin theta`
Vertical component is unchanged relative to trolley and ground. Now time of flight`=(2u sin theta)/g`
Time of flight remains unchanged relative to trolley & ground. Hence right choice is (a).