In previous problem, the horizontal range of the stone is:

Options

A. `((u+v)^(2))/g`
B. `(|vecu+vec v|^(2))/g`
C. `(2v^(2))/g`
D. `(2uv)/g`

Answer

d

Explanation

From previous solution,
`v_(0)sin theta=u`.......(i)
`v_(0)cos theta=u`.......(ii)
Range `=(v_(0)^(2)sin 2 theta)/g=(2v_(0)sin theta v_(0) cos theta)/g`
`R=(2vu)/g`