The ratio of the range of the particle and its maximum range in the inclined plane is:

Options

A. `1:2`
B. `1:sqrt(2)`
C. `1:sqrt(3)`
D. `1:1`

Answer

d

Explanation

`R=v_(0)cos 30^(@) T-1/2g sin 30^(@) T^(2)`
`=10 (sqrt(3))/2-2/(sqrt(3))-1/2xx10xx1/2(2/(sqrt(3)))^(2)=20/3`
`R_(max)=(v_(0)^(2))/(g(1+sin theta_(0)))`
`=(10^(2))/(10(1+sin theta_(0)))`
`=(10^(2))/(10(1+sin 30^(@)))=20/3`
So, `R/(R_(max))=1`