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A particle is projected from the incline...

A particle is projected from the inclined plane at angle `37^(@)` with the inclined plane in upward direction with speed `10m//s`. The angle of inclined plane with horizontal is `53^(@)`. Then the maximum height attained by the particle from the inclined plane will be-

A

`3m`

B

`4m`

C

`5m`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
a
Maximum height from incident plane is
`H=(u_(bot)^(2))/(2a_(bot))=((10sin 37^(@))^(2))/(2g cos 53^(@))=3m`
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