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A ball is thrown from a point with a spe...

A ball is thrown from a point with a speed 'v^(0)' at an elevation angle of `theta` . From the same point and at the same instant , a person starts running with a constant speed `('v_(0)')/(2) ` to catch the ball . Will the person be able to catch the ball ? If yes, what should be the angle of projection `theta` ?

A

yes, `60^(@)`

B

yes, `30^(@)`

C

No

D

yes, `45^(@)`

Text Solution

Verified by Experts

The correct Answer is:
a

For the person to be able to catch the ball, the horizontal component of velocity of the ball should be same as the speed of the person,
i.e, `v_(0)cos theta=(v_(0))/2 or cos theta=1/2 or theta=60^(@)`
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Knowledge Check

  • A ball is thrown from a point with a speed v_0 at an angle of projection theta . From the same point and at the same instant, a person starts running with a constant speed v_0/2 to catch the ball. Will the person be able to catch the ball ? If yes, what should be the angle of projection ?

    A
    Yes, `60^@`
    B
    Yes, `30^@`
    C
    No
    D
    No, `45^@`
  • A ball is thrown from a point with a speed v_0 at an angle of projection theta . From the same point and at the same instant, a person starts running with a constant speed v_0/2 to catch the ball. Will the person be able to catch the ball ? If yes, what should be the angle of projection ?

    A
    Yes, `60^@`
    B
    Yes, `30^@`
    C
    No
    D
    No, `45^@`
  • A ball is thrown from a point with a speed V_(0) ,at an angle of projection theta .From the same point and at the same instance a person starts running with a constant speed V_(0)/sqrt2 to catch the ball will the person be able to catch the ball? If yes, what should be the angle of projection

    A
    yes, `60^(@)`
    B
    yes, `30^(@)`
    C
    No
    D
    yes, `45^(@)`
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